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Introductory BJT Circuits

Consider again the circuit of Figure 96. We first do a DC analysis using the DC model of Section 8.2.3. You can either re-draw the circuit substituting the model of Figure 100 for the transistor, or simply keep the same diagram and write explicitly the algebraic equations

 \begin{displaymath}V_{BE} = 0.7 \ V, \ \ \ I_C = \beta I_B, \ \ \ I_E = I_B + I_C
\end{displaymath} (93)

corresponding to the DC model.

The left part of the circuit gives, using KVL,

VBB = IB RB + VBE

and hence the base current is given by

 \begin{displaymath}I_B = \frac{V_{BB} - 0.7 \ V}{R_B} .
\end{displaymath} (94)

If VBB is given, this can be solved to get IB. The right part of the circuit gives

VCC = IC RC + VCE

This gives a linear relationship (load line)  for IC and VCE:

 \begin{displaymath}I_C = \frac{V_{CC} - V_{CE}}{R_C}
\end{displaymath} (95)

Since this must equal $\beta I_B$, one can solve for VCE to find the quiescent or operating point Q.     This is often done graphically, as shown in Figure 103.


  
Figure 103: DC load line for the circuit of Figure 96.
\begin{figure}
\begin{center}
\epsfig{file=images/bjtimg12.eps}\end{center}\end{figure}

The operating point Q can be anywhere on the load line that is intersected by a collector characteristic. Note that this is the same as the diode method where one uses device characteristics in combination with circuit equations.

Importantly, VCE determination allows one to verify if the initial assumption of active bias is correct!



 
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